Home
Class 12
PHYSICS
A simple potentiometer circuit is shown ...

A simple potentiometer circuit is shown in the figure. The internal resistance of the battery is negligible. AB is a uniform wire of length 100cm and resistance `2Omega` What would be the length AC for zero galvanometer deflection (in mm)?

Text Solution

Verified by Experts

The correct Answer is:
825
`I=(4)/(2.4+2)=(4)/(4.4)=(1)/(1.1)=(10)/(11)`
If `AC=x`
Then `R_(AC)=(x)/(50)Omega`
`(10)/(11)xx(x)/(50)=1.5 rArr x=1.5xx5xx11=82.5cm`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • JEE MAIN REVISION TEST - 1 | JEE - 2020

    VMC MODULES ENGLISH|Exercise PHYSICS ( SECTION 2)|5 Videos

  • JEE MAIN REVISION TEST - 1 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS - SECTION 2|5 Videos

  • JEE MAIN REVISION TEST - 10| JEE -2020

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

A simple potentiometer circuit is shown in figure. The internal resistance of 4V battery is negligible. AC is he uniform wire of length 100 cm and resistance 2 Omega .What would be the length of AB for which galvanometer shows zero deflection.

A simple potentiometer circuit is shown in figure . The internal resistance of 4 V battery is negligble AC is the uniform wire of length 100 cm , and resistance 2 Omega . What would be the length of AB for which galivanometer shows zero deflection .

A simple potentiometer circuit is shown in the figure. The internal resistance of 5 V battery is 0.6 Omega wire of length 4 m and resistance 0.5 Omega per meter. The length AB for which galvanometer shows zero deflection is

In the potentiometer circuit shown in the figure the internal resistance of the 6V battery is 1Omega and length of the wire AB is 100 cm . When AD = 60 cm , the galvanometer shows no deflection . The EMF of the cell C is (the resistance of the wire AB is 2Omega )

In the figure shown wire AB has a length of 100 cm and resistance 8Omega . Find the balance point length l .

For the potentiometer arrangement shown in the figure, length of wire AB is 100 cm and its resistance is 9 Omega . Find the length AC for which the galvanometer G will show zero deflection.

The reading of a galvanometer connected in the circuit is zero. If the internal resistance of a battery is zero then find the value of X.

In the below circuit , AB is a wire of length 100 cm with 5Omega resistance . If there is no deflection in the galvanometer , the current flowing in the wire AB is

A meter bridge setup is shown in the figure. If there is null deflection in galvanometer when length AC = 20 cm, then the value of resistance R is

A potentiometer circuit has been setup for finding. The internal resistance of a given cell. The main battery used a negligible internal resistance. The potentiometer wire itsefl is 4 m long. When the resistance, R , connected across the given cell, has value of (i) Infinity (ii)9.5 Omega , the 'balancing length' , on the potentiometer wire are found to be 3 m and 2.85 m , respectively. The value of internal resistance of the cell is

Home
Profile