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Ge and Si diodes start conducting at 0.3...

Ge and Si diodes start conducting at 0.3 V and 0.7 V respectively. In the following figure if Ge diode connection are reversed, the value of `V_(o)` changes by :
(assume that the Ge diode has large breakdown voltage)

A

0.8 V

B

0.6 V

C

0.4 V

D

0.2 V

Text Solution

Verified by Experts

The correct Answer is:
C

Initially

Silicon diode will behave like open circuit
So `V_(0) = 12 - 0.3 = 11.7 V`
Silicon diode will behave like open circuit
So `V_0 = 12 - 0.3 = 11.7 V`
Finally Ge is reverse biased and it will not conduct as per assumption so

`V_(0) = 12 - 0.7 = 11.3 V`
Change = 0.4 V
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