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A mass of 10 kg is suspended vertically ...

A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of `45^(@)` at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g`=10 ms^(-2)`)

A

70 N

B

140 N

C

100 N

D

200 N

Text Solution

Verified by Experts

The correct Answer is:
C

`T_(1)sin 45^(@)=T_(2)=100`
`F_(2)T_(1)cos 45^(@)`
`"So "T_(1)=140N=F=100N`
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