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The Wheatstone bridge shown in Fig. here...

The Wheatstone bridge shown in Fig. here, gets balanced when the carbon resistor used as `R_(1)` has the colour code (Orange, Red, Brown). The resistors `R_(2) and R_(4)` are `80 Omega` and `40 Omega`, respectively.
Assuming that the colour code for the carbon resistor, used as `R_(3)`, would be:

A

Brown, Blue, Black

B

Grey, Black, Brown

C

Red, Green, Brown

D

Brown, Blue, Brown

Text Solution

Verified by Experts

The correct Answer is:
D
`R_(1)=32xx10^(1)=320Omega`
`R_(2)=80Omega, R_(4)=40Omega`
`R_(1)R_(4)=R_(2)R_(3) rArr R_(3)=(R_(1)R_(4))/(R_(2))=(320xx40)/(80)=160Omega rArr R_(3)= 16xx10^(1)`
Colour code = Brown, Blue, Brown
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