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A current of 2 mA was passed through an ...

A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11 V is connected across it is

Text Solution

Verified by Experts

The correct Answer is:
11
`P=i^(2)R`
`rArr 4.4 = (2xx10^(-3))^(2)xxR=1.1xx10^(6)Omega`
Now, `P=(V^(2))/(R)=(11xx11)/(1.1xx10^(6))W=11xx10^(-5)W`
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