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Two kg of a monoatomic gas is at a press...

Two kg of a monoatomic gas is at a pressure of `4 xx 10^(4) N//m^(2)`. The density of the gas is `8 kg//m^(3)`. What is the order of energy of the gas due to its thermal motion ?

A

`10^(5)J`

B

`10^(4)J`

C

`10^(3)J`

D

`10^(6)J`

Text Solution

Verified by Experts

The correct Answer is:
B
`U=(f)/(2)n RT=(f)/(2)PV=(f)/(2)xxPxx("mass")/("density")`
`rArr U=(3)/(2)xx4xx10^(4)xx(2)/(8)J=1.5xx10^(4)J`
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