Home
Class 12
PHYSICS
Two identical spherical balls of mass M ...

Two identical spherical balls of mass M and radius R each are stuck on two ends of a rod of length 2R and mass M (see figure). The moment of inertia of the system about the axis passing perpendicularly through the centre of the rod is

A

`(209)/(14)MR^(2)`

B

`(152)/(15)MR^(2)`

C

`(17)/(15)MR^(2)`

D

`(137)/(15)MR^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`I=2((2)/(5) MR^(2)+MR^(2)4)+(MR^(2))/(3)=(137)/(15)MR^(2)`
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST-3 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

  • JEE MAIN REVISION TEST-3

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 1)|3 Videos

  • JEE Main Revision Test-6 | JEE-2020

    VMC MODULES ENGLISH|Exercise PHYSICS|2 Videos

Similar Questions

Explore conceptually related problems

A disc of mass m and radius R is attached to a rectangular plate of the same mass m, breadth R and length 2R as shown in figure. The moment of inertia of the system about the axis AB passing through the centre of the disc and along the plane is I = 1/(alpha) (31/3 m R^2) .

Two spheres each of mass M and radius R//2 are connected with a massless rod of length R . Find the moment of inertia of the system about an axis passing through the centre of one of the sphere and perpendicular to the rod

A circular disc D_(1) of mass M and radius R has two identical disc D_(2) and D_(3) of the same mass M and radius R attached rigidly at its opposite ends (see figure). The moment of inertia of the system about the axis OO, passing through the centre of D_(1) as shown in the figure, will be :

Two masses each of mass M are attached to the end of a rigid massless rod of length L . The moment of interia of the system about an axis passing centre of mass and perpendicular to its length is.

Two identical spheres each of mass 1.20 kg and radius 10.0 cm are fixed at the ends of a light rod so that the separation between the centers is 50.0 cm. Find the moment of inertia of the system about an axis perpendicular to the rod passing through its middle point.

Two uniform solid of masses m_(1) and m_(2) and radii r_(1) and r_(2) respectively, are connected at the ends of a uniform rod of length l and mass m . Find the moment of inertia of the system about an axis perpendicular to the rod and passing through a point at a distance of a from the centre of mass of the rod as shown in figure.

Two point masses m and 4m are connected by a light rigid rod of length l at the opposite ends. Moment of inertia of the system about an axis perpendicular to the length and passing through the centre of mass is

A system of uniform rod of mass m and length 2R and a uniform disc of m and radius R are as shown in the figure. The moment of inertia of the system about the axis OO^' (perpendicular to plane of disc) will be

Four rings each of mass M and radius R are arranged as shown in the figure. The moment of inertia of the system about YY' will be

Three rings each of mass M and radius R are arranged according to the figure. The moment of inertia of this system about an axis XX' on its plane would be