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Two stars of masses 3 xx 10^(31) kg each...

Two stars of masses `3 xx 10^(31)` kg each, and at distance `2 xx 10^(11)` m rotate in a plane about their common centre of mass O. A meteorite passes through O moving perpendicular to the star's rotation plane. In order to escape from the gravitational field of this double star, the minimum speed that meteorite should have at O is (Take Graviational constant `G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)`)

A

`2.4xx10^(4)m//s`

B

`3.8xx10^(4)m//s`

C

`1.4xx10^(5)m//s`

D

`2.8xx10^(5)m//s`

Text Solution

Verified by Experts

The correct Answer is:
D
`(1)/(2)mv^(2)=(2GMm)/(R)rArr v=sqrt(12xx10^(20)xx6.67xx10^(-11))=2.82xx10^(5)m//s`
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