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For the circuit shown below, the current...

For the circuit shown below, the current through the Zener diode is

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Verified by Experts

The correct Answer is:
9
Voltage drop across `10kOmega=50V`
`i_(10kOmega)=(50)/(10xx10^(3))A=5mA`
Voltage drop across `5kOmega=70V`
`i_(5kOmega)=(70)/(5xx10^(3)=14mA`
Hence, current through zener diode `=(14-5)mA=9mA`
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