A slab is subjected to two forces `vec F_(1) and vec F_(2)` of same magnitude F as shown in the figure . Force `vec F_(2)` is in XY-plane while force `F_(1)` acts along z-axis at the point `(2 vec I + 3 vec j)` .The moment of these forces about point O will be :
A
`(3hati+2hatj-3hatk)F`
B
`(3hati-2hatj-3hatk)F`
C
`(3hati+2hatj+3hatk)`
D
`(3hati-2hatj+3hatk)F`
Text Solution
Verified by Experts
The correct Answer is:
D
`vectau_1=(2hati+3hatj)xx(hatk)F=(-2hatj+3hati)F` `vectau_2=(6hatj)xx(F/2)(-hati)=3Fhatk` So, `vectau=(3hati-2hatj+3hatk)F`
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VMC MODULES ENGLISH-JEE Main Revision Test-6 | JEE-2020 -PHYSICS
