A hydrogen atom initially in the ground state is excited by absorbing a photon of wavelenght 980 Å.The redius of the atom in the excited state ,in terms of Bohr radius `a_(0)` will be : `(hc= 12500 eV- Å)`
A
`9a_0`
B
`25a^0`
C
`16a^@`
D
`4a^@`
Text Solution
Verified by Experts
The correct Answer is:
C
`E=(hc)/lambda=12500/980 eV approx ` 12.75 eV This is the energy difference between n=1 & n=4 Also, `r=r_0 n^2/z` So, `r/r_0=16`
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VMC MODULES ENGLISH-JEE Main Revision Test-6 | JEE-2020 -PHYSICS
