Two equal resistances when connected in series to a battery ,consume electric power of 60 W .If these resitances are now connected in parealled combination to the same battery ,the electric power cansumed will be :
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B, D
`P_0=1/R(V_0/2)^2xx2=V_0^2/(2R)` `P=V_0^2/Rxx2` So, `P/P_0`=4 `because P_0`=60w `rArr` P = 60 x 4 = 240 w
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