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In the figure shown, what is the current...

In the figure shown, what is the current (in Ampere) drawn from the battery ? You are given:
`R_(1) =15 Omega,R_(2)=10 Omega,R_(3)=20Omega,R_(4)=5Omega`,
`R_(5)=25Omega,R_(6)=30Omega,E=15V`

A

` 13//24 `

B

` 20 // 3 `

C

` 7// 18 `

D

` 9// 32 `

Text Solution

Verified by Experts

` R _ (eq ) = (160)/(3) , i= (V)/(R _ eq) = (15 ) /(160//3) = ( 9 ) /(32 ) `
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