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In a line of sight radio communication, ...

In a line of sight radio communication, a distance of about `50` is Kept between the transmitting and receiving entennas. If the height of the receiving antenna is `70m` , then the minimum height fof the transmitting antenna should be:
`("Radius of the Earth"=6.4xx10^(6)m)`.

A

` 51 m `

B

` 40 m `

C

` 20 m `

D

` 32 m `

Text Solution

Verified by Experts

` d = sqrt ( 2 Rh_ T ) + sqrt ( 2 Rh _ R ) `
` 50 xx 10 ^ ( 3 ) = sqrt ( 2 xx 6.4 xx 10 ^( 6) xx 70 ) + sqrt ( 2 xx 6.4 xx 10 ^( 6) xx h_ R ) `
` rArr h_R = 32 m `
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