Home
Class 12
PHYSICS
Two particles move at right angle to eac...

Two particles move at right angle to each other. Their de Broglie wavelenghts are `lambda_(1)` and `lambda_(2)` respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelenght `lambda`, of the final particle, is given by:

A

`lamda=sqrt(lamda_1lamda_2)`

B

`2/lamda=1/lamda_1+1/lamda_2`

C

`1/lamda^2=1/lamda_1^2+1/lamda_2^2`

D

`lamda=(lamda_1+lamda_2)/2`

Text Solution

Verified by Experts

The correct Answer is:
C

Conserver momentum
along `x:(h)/(lamda_1)+0=h/lamdacostheta`
along y :`h/(lamda_2)+0=h/lamdasintheta`
Squaring and adding
`h^2(1/(lamda_1^2+lamda_2^2))=h^2/lamda_2implies1/lamda_2=1/lamda_1^2+1/lamda_2^2`
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST - 10| JEE -2020

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

  • JEE MAIN REVISION TEST - 1 | JEE - 2020

    VMC MODULES ENGLISH|Exercise PHYSICS ( SECTION 2)|5 Videos

  • JEE MAIN REVISION TEST - 12

    VMC MODULES ENGLISH|Exercise PHYSICS|25 Videos

Similar Questions

Explore conceptually related problems

Two identical non-re,aticivistic particles move at right angle to each other. Possesing de Broglie wavelength lambda_(1) and lambda_(2) Find the Broglie wavelength of each particle in the frame of their centre of inertia.

de Broglie wavelength of a moving particle is lambda . Its momentum is given by :

Two particles of masses m and 2m have equal kinetic energies. Their de Broglie wavelengths area in the ratio of:

Two particles A and B of de-broglie wavelength lambda_(1) and lambda_(2) combine to from a particle C. The process conserves momentum. Find the de-Broglie wavelength of the particle C. (The motion is one dimensional).

Two particles A and B of de-broglie wavelength lambda_(1) and lambda_(2) combine to from a particle C. The process conserves momentum. Find the de-Broglie wavelength of the particle C. (The motion is one dimensional).

An electron, a neutron and an alpha particle have same kinetic energy and their de-Broglie wavelength are lambda_e, lambda_n and lambda_(alpha) respectively. Which statement is correct about their de-Broglie wavelengths?

Two particles of de-broglie wavelength lamda_(x) and lamda_(y) are moving in opposite direction. Find debroglie wavelength after perfectly inelastic collision:

For a proton accelerated through V volts , de Broglie wavelength is given as lambda =

The ratio of the de Broglie wavelength of a proton and alpha particles will be 1:2 if their

The ratio of the de Broglie wavelength of a proton and alpha particles will be 1:2 if their