A uniform cable of mass 'M' and length 'L' is placed on a horizontal surface such that its `((1)/(n))^(th)` part is hanging below the edge of the cable upto the surface, the work done should be :

Options

A. `(MgL)/(2n^(2))`
B. `(MgL)/(n^(2))`
C. nMgL
D. `(2MgL)/(n^(2))`

Answer

A

Explanation

Work-done will be equal to rise in potential energy of suspended section
`:.W=(mg)/(L) xx L/n xx (L)/(2n)=(MgL)/(2n^(2))`