A ball is through vertically up (taken as +z-axis) from the ground. The correct momentum-height (p-h) diagram is :

Options

A.
B.
C.
D.

Answer

C

Explanation

`V^(2)=u^(2)-2gh rArr m^(2)v^(2)=m^(2)u^(2)-2mgh`
`rArr p^(2)=A-Bh` ( where `A=m^(2)u^(2), b=2mg`)
Cleary it is parabolic functions.
Starting from ground momentum first decreases and then becomes zero at highest position. Therefore it increases iin -ve direction. Hence `3^(rd)` option is correct.