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A capacitor with capacitance 5 mu F is c...

A capacitor with capacitance `5 mu F` is chrged to `5 mu C`. If the plates are pulled apart to reduce the capacitance to `2 mu F`, how much work is done ?

A

`2.55xx10^(-6)J`

B

`3.75xx10^(-6)J`

C

`6.25xx10^(-6)J`

D

`2.16xx10^(-6)J`

Text Solution

Verified by Experts

The correct Answer is:
B
`W=|Delta U|=(Q^(2))/(2C_(1))-(Q^(2))/(2C_(2))=3.75xx10^(-6)J`
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