A simple pendulum oscillating in air has period T. The bob of the pendulum is completely immersed in a non-viscours liquid. The density of the liquid is `(1)/(16)th` of the material of the bob. If the bob is inside liquid all the time, its period of scillation in this liquid is :

Options

A. `2T sqrt((1)/(10))`
B. `4 T sqrt((1)/(15))`
C. `4 T sqrt((1)/(14))`
D. `2T sqrt((1)/(14))`

Answer

B

Explanation

`T=2pi sqrt(l/g)& T'=2pi sqrt((1)/(g-(g//16))) " " ( :' "Buoyancy" = (mg)/(16))`
`:.T=Txx(1)/(sqrt(1-1/16))=4Txx sqrt((1)/(15))`