The number of water molecule(s) not coordinated to copper ion directly in `CuSO_(4). 5H_(2)O` , is _______ .

Explanation

To determine the number of water molecules not coordinated to the copper ion in the compound CuSO₄·5H₂O, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Composition of CuSO₄·5H₂O**:
- The compound consists of one copper sulfate (CuSO₄) and five water molecules (5H₂O).

2. **Understand Coordination in the Compound**:
- In coordination compounds, certain molecules act as ligands, which are directly bonded to the central metal ion (in this case, copper ion).
- The copper ion (Cu²⁺) can coordinate with water molecules.

3. **Determine the Number of Coordinated Water Molecules**:
- In CuSO₄·5H₂O, typically, four water molecules coordinate directly to the copper ion, forming a complex ion [Cu(H₂O)₄]²⁺.
- This means that these four water molecules are acting as ligands.

4. **Identify the Non-Coordinated Water Molecule**:
- Out of the five water molecules, one water molecule remains uncoordinated and is present as a crystal water (or water of hydration).
- Therefore, only one water molecule is not directly bonded to the copper ion.

5. **Conclusion**:
- The number of water molecules not coordinated to the copper ion directly in CuSO₄·5H₂O is **1**.

### Final Answer:
The number of water molecule(s) not coordinated to the copper ion directly in CuSO₄·5H₂O is **1**.

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