Home
Class 12
CHEMISTRY
A hydrated solid X on heating initally g...

A hydrated solid X on heating initally gives a monohydrated compound Y. Y upon heating above 373 K leads to an anhydrous white powder Z, X and Z respectively, are:

A

Baking soda and soda ash

B

Washing soda and dead burnt plaster

C

Baking soda and dead burnt plaster

D

Washing soda and soda ash

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify the hydrated solid X, the monohydrated compound Y, and the anhydrous white powder Z based on the heating process described. ### Step-by-Step Solution: 1. **Identify the Hydrated Solid (X)**: - The problem states that we have a hydrated solid X that on heating gives a monohydrated compound Y. A well-known hydrated compound that fits this description is washing soda, which is sodium carbonate decahydrate (Na2CO3·10H2O). 2. **Heating X to form Y**: - When washing soda (Na2CO3·10H2O) is heated, it loses water molecules. The first stage of heating results in the formation of a monohydrated compound, which is sodium carbonate monohydrate (Na2CO3·H2O). This is our compound Y. 3. **Heating Y to form Z**: - The next part of the question states that Y (Na2CO3·H2O) upon further heating above 373 K leads to an anhydrous white powder Z. When sodium carbonate monohydrate is heated above 373 K, it loses the remaining water molecule and forms anhydrous sodium carbonate (Na2CO3), which is the white powder Z. 4. **Conclusion**: - Therefore, we can summarize the compounds as follows: - X (hydrated solid) = Na2CO3·10H2O (Washing Soda) - Y (monohydrated compound) = Na2CO3·H2O (Sodium Carbonate Monohydrate) - Z (anhydrous white powder) = Na2CO3 (Soda Ash) ### Final Answer: - X = Washing Soda (Na2CO3·10H2O) - Y = Sodium Carbonate Monohydrate (Na2CO3·H2O) - Z = Soda Ash (Na2CO3)
To solve the problem, we need to identify the hydrated solid X, the monohydrated compound Y, and the anhydrous white powder Z based on the heating process described. ### Step-by-Step Solution: 1. **Identify the Hydrated Solid (X)**: - The problem states that we have a hydrated solid X that on heating gives a monohydrated compound Y. A well-known hydrated compound that fits this description is washing soda, which is sodium carbonate decahydrate (Na2CO3·10H2O). 2. **Heating X to form Y**: ...
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST - 13

    VMC MODULES ENGLISH|Exercise CHEMISTRY (SECTION 2)|5 Videos

  • JEE MAIN REVISION TEST - 12

    VMC MODULES ENGLISH|Exercise CHEMISTRY|25 Videos

  • JEE MAIN REVISION TEST - 18

    VMC MODULES ENGLISH|Exercise CHEMISTRY - SECTION 2|5 Videos

Similar Questions

Explore conceptually related problems

In this sequence X, Y , Z are respectively:

Hydrolysis of SiCl_(4) gives compound 'X' and HCl on heating to 1000^(@)C 'X' loses water and forms 'Y'. Identify 'X' and 'Y' respectively.

A white solid X on heating gives a white solid Y and an acid gas Z. gas Z is also given out when X reacts with an acid. The compound Y is also formed if caustic soda is left open in the atmosphere. X, Y and Z are

Reaction of an inorganic sulphite X with dilute H_(2)SO_4) generates compound Y . Reaction of Y with NaOH gives X . Further , the reaction of X and Y and water affords compound Z . Y and Z respectively are :

An orange solid (X) on heating, gives a colourless gas (Y) and a only green residue (Z). Gas (Y) on treatment with Mg, produces a white solid substance……

X,Y and Z in the above graph are

A metal X reacts with water to produce a highly combustible gas Y, and a solution Z. another metal P reacts with Z to give the same gas Y. X,Y,Z and P respectively are

B_2H_6+NH_3to Addition compound (X) overset(450 K)to Y+Z(g) In the above sequence Y and Z are respectively :

A colourless water soluble solid (X) on heating gives equimolar quantities of (Y) and (Z). Y gives dense white fumes with HCl and Z does so with NH_(3) . Y gives brown ppt. with K_(2)HgI_(4) (Nessler's reagent) and Z gives white precipitate with nitrates of Ag^(+), Pb^(2+) and Hg^(+) . What is X ?

A colourless water soluble solid (X) on heating gives equimolar quantities of (Y) and (Z). Y gives dense white fumes with HCl and Z does so with NH_(3) . Y gives brown ppt. with K_(2)Hgl_(4) (Nesslers reagent) and Z gives white precipitate with nitrates of Ag^(+), Pb^(2+) and Hg^(+) . What is X ?