Which of the following is NOT a Correct method of the preparation of benzylamine from cyanobenzene?

Options

A. (i) `HCl//H_(2)O` (ii) `NaBH_(4)`
B. (i) `SnCl_(2) + HCl` (gas) (ii) `NaBH_(4)`
C. `H_(2)//Ni`
D. (i) `LiAIH_(4)` (ii) `H_(3)O^(+)`

Explanation

To determine which method is NOT a correct way to prepare benzylamine from cyanobenzene, let's analyze each option step by step.

### Step 1: Understand the Structures
- **Cyanobenzene**: This compound has a cyano group (–C≡N) attached to a benzene ring.
- **Benzylamine**: This compound has an amine group (–NH2) attached to a benzyl group (–CH2–C6H5).

### Step 2: Analyze the Options
1. **Option 1: HCl + H2O + NaBH4**
- When cyanobenzene reacts with HCl and H2O, it undergoes hydrolysis to form an intermediate (likely an amide, –C(=O)NH2).
- NaBH4 is a reducing agent, but it does not reduce the amide to the desired benzylamine. Therefore, this method does not yield benzylamine.

2. **Option 2: SnCl2 + HCl followed by NaBH4**
- The reaction of cyanobenzene with SnCl2 and HCl leads to the formation of an imine (–C=N–).
- NaBH4 can reduce the imine to the corresponding amine, which is benzylamine. This method is valid.

3. **Option 3: H2 + Ni**
- Hydrogenation of cyanobenzene using H2 in the presence of a nickel catalyst will convert the cyano group (–C≡N) to an amine group (–NH2). This method is valid for producing benzylamine.

4. **Option 4: LiAlH4 + H3O+**
- Lithium aluminum hydride (LiAlH4) is a strong reducing agent that can reduce the cyano group (–C≡N) to an amine (–NH2). After hydrolysis with H3O+, this will yield benzylamine. This method is also valid.

### Conclusion
After analyzing all the options, we find that **Option 1: HCl + H2O + NaBH4** is NOT a correct method for the preparation of benzylamine from cyanobenzene.

### Final Answer
**Option 1: HCl + H2O + NaBH4 is NOT a correct method for the preparation of benzylamine from cyanobenzene.**