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A stationary source of sound is emitting...

A stationary source of sound is emitting sound of frequency `500Hz`. Two observers `A` and `B` lying on the same line as the source, observe frequencies `480Hz` and `530 Hz` respectively. The velocity of `A` and `B` respectively are (in `m//s`), speed of sound `=300m//s`.

A

8,18

B

16,14

C

12,18

D

12,16

Text Solution

Verified by Experts

The correct Answer is:
C
Higher frequency heard will be when the observer would move towards the source and lower will be when observe moves away from the source.
`therefore 530 = 500 [(300- V_(01))/(300-0)] rArr V_(01) = 18 m//s`
Also, `480 = 500[(300-V_(02))/(300-0)] rArr V_(02) = 12 m//s`
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