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A Circular ring of radius 3a is uniforml...

A Circular ring of radius `3a` is uniformly charged with charge `q` is kept in `x-y` plane with center at origin. A particle of charge `q` and mass `m` is projected frim `x=4` towards origin. Find the minimum speed of projection such that it reaches origin.

A

`sqrt(2)/m (1/15 q^(2)/(4 pi epsilon_(0)a))^(1//2)`

B

`sqrt(2/m)(2/15 q^(2)/(4pi epsilon_(0)a)^(1//2))`

C

`sqrt(2/m)(4/15 q^(2)/(4pi epsilon_(0)a)^(1//2))`

D

`sqrt(2/m)(1/5 q^(2)/(4pi epsilon_(0)a)^(1//2))`

Text Solution

Verified by Experts

The correct Answer is:
B


From energy conservation,
`U_(1) + k_(1) = U_(f) + k_(f)`
`(k(q)(q))/sqrt((3a)^(2)+(4a)^(2)) + 1/2mv_("min")^(2) =(k(q)(q))/(3a)+0 rArr V_("min") = sqrt(2/m)(2/15 q^(2)/(4pi epsilon_(0)a)^(1//2))`
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