In an experiment, the resistance of a material is plotted as a function of temperature (in some range).As shown in the figure, it is a straight line.

One may conclude that :

Options

A. `R(T)= R_(0)e^(-T^(2)//T_(0)^(2))`
B. `R(T) = R_(0)/T^(2)`
C. `R(T) = R_(0)e^-(T_(0)^(2)//T^(2))`
D. `R(T) = R_(0)e^(T^(2)//T_(0)^(2))`

Answer

C

Explanation

In R varies linearly with `1/T^(2)`
So, ln `R=-M(1/T^(2))+c [m gt 0, c gt 0]`
Using, `y=-mx +c`
`R=e^(c-m/T^(2))=e^( c).e^(m/T^(2))` or `R=R_(0)e^(-m//T^(2))` type of form will do good