Ethylamine `(C_(2)H_(5)NH_(2))` can be obtained from N-ethylphtahlimide on treatment with:

Options

A. `NH_(2)NH_(2)`
B. `NaBH_(4)`
C. `H_(2)O`
D. `CaH_(2)`

Explanation

To solve the problem of obtaining ethylamine (C₂H₅NH₂) from N-ethylphthalimide, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Starting Material**:
The starting compound is N-ethylphthalimide. Its structure consists of a phthalimide ring with an ethyl group attached to the nitrogen atom.

2. **Understand the Reaction Type**:
The reaction we will be using is known as the Gabriel synthesis. This involves the use of hydrazine (NH₂NH₂) to hydrolyze the N-ethylphthalimide.

3. **React N-ethylphthalimide with Hydrazine**:
When N-ethylphthalimide is treated with hydrazine (NH₂NH₂), it undergoes a reaction where the hydrazine attacks the carbonyl carbon of the phthalimide.

4. **Formation of Ethylamine**:
The reaction leads to the cleavage of the phthalimide ring and results in the formation of ethylamine (C₂H₅NH₂) along with the release of phthalic acid or its derivatives.

5. **Final Product**:
The final product of this reaction is ethylamine (C₂H₅NH₂), confirming that the treatment of N-ethylphthalimide with hydrazine yields the desired amine.

### Conclusion:
Thus, the correct reagent to treat N-ethylphthalimide to obtain ethylamine is **hydrazine (NH₂NH₂)**.