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The figure shows a square loop L of side...


The figure shows a square loop L of side 5 cm which is connected to a network of resistances. The whole setup is moving towards right with a contant speed of 1 cm s–1 . At some instant, a part of L is in a uniform magnetic field of 1 T, perpendicular to the plane of the loop. If the resistance of L is 1.7 Ω, the current in the loop at that instant will be close to:

A

`60muA`

B

`115muA`

C

`170muA`

D

`150muA`

Text Solution

Verified by Experts

The correct Answer is:
C
`(1)/(R_(1))=(1)/(4)+(1)/(2)," "R_("eq")=R_(1)+1.7=(4)/(3)+1.7`
`(1)/(R_(1))=(1+2)/(4)," "R_(eq)=(4+5.1)/(3)`
`R_(1)=(4)/(3)," "R_(eq)=(9.1)/(3)`
`epsilon=Bvl`
`epsilon=IR_(eq)," "l=(V)/(R_("eq"))`
`l=(5xx10^(-4))/((9.1)/(3))=(15xx10^(-4))/(9.1)`
`l=1.648xx10^(-4)," "l=164.8xx10^(-6)," "l=164.8muA`
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