Water flows into a large tank with flat bottom at the rate of `10^(-4) m^(3)s^(-1)`. Water is also leaking out of a hole of area 1 `cm^(2)` at its bottom. If the height of the water in the tank remains steady, then this height is :

Explanation

`10^(-4) = 10^(-4) xx V xx 1/2`
` rArr V = 2 ms^(-1)`
` rho gh = 1/2 rho V^2`
` V = sqrt(2gh) rArr h = (V^2)/(2g) = (2 xx 2)/(2 xx 10) = .2m = 20 cm `