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A conducting rod of length 2l is rotatin...

A conducting rod of length 2l is rotating with constant angular speed `omega` about its perpendicular bisector . A uniform magnetic field `vecB` exists parallel to the axis of rotation . The e.m.f induced between two ends of the rod is

A

`B omega l^(2)`

B

`(1)/(2)B omegal^(2)`

C

`(1)/(8)B omega l^(2)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D

Potential difference between
O and A is `V_(A)-V_(O)=(1)/(2)Bl^(2)omega`
O and B is `V_(B)-V_(O)=(1)/(2)Bl^(2)omega`
So `V_(A)-V_(B)=0`
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