Two infinite line charges with uniform linear charge densities `+ lamda & - lamda` are kept in such a way that the angle between them is `30^(@).` The electric field at the symmetric point P at a perpendicular distance r from each line charge is given by:
A
`(lamda)/(2 pi in_(r))((1- sqrt3) haty - (x)/(2))`
`(lamda)/(2 pi in _(0) r)((1 - (sqrt3)/(2))haty - (hatx )/(2))`
D
`(lamda)/(2 pi in _(0) r)((1 +(sqrt3)/(2))haty - (hatx )/(2))`
Text Solution
Verified by Experts
The correct Answer is:
D
`vecE= (lamda)/(2piin _(0) r) cos 60^(@) hatx + ((lamda)/(2pi in _(0)r)+ (lamda)/(2 pi in _(0) r ) sin 60^(@))haty7 ` `= (lamda)/(2 pi in _(0) r)[(1+ (sqrt3)/(2)) haty + 1/2 hatx]`
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VMC MODULES ENGLISH-JEE MAIN REVISON TEST-23-PHYSICS (SECTION 2)
