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The current I (1) (in A) flowing through...

The current `I _(1)` (in A) flowing through `3 Omega` resistor in the following circuit is:

A

`3A`

B

`1A`

C

`4A`

D

`2A`

Text Solution

Verified by Experts

The correct Answer is:
D
`I=(12)/(2+2) A=(12)/(4) A 3A:" " I _(1) = (6)/(6 +3) I = (2I )/(3) =2A`
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