A polaroid sheet is rotated in between two crossed polaroids `P _(1) and P _(2)` At what ` theta` of pass axis of polaroid sheet with pass-axis of polaroid `P _(1)` must be kept so that the final intensity of transmitted light be maximum? (P = polaroid sheet axis)
A
`pi/4`
B
`pi/6`
C
`pi/3`
D
`pi/2`
Text Solution
Verified by Experts
The correct Answer is:
A
Intensity of light after passing through `P _(1) be I _(0)` Thus, Intensity of light passing through `P _(2)` will be `I _(P_(2)) = (I_(0) cos ^(2)) cos ^(2) (90^(@)-theta)= I_(0) cos ^(2) theta sin ^(2) theta = (I_(0))/(4) sin 2 theta` For maximum `I _(P_(2)) implies sin 2 theta =1 " " therefore " " theta = (pi)/(4)`
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VMC MODULES ENGLISH-JEE MAIN REVISON TEST-23-PHYSICS (SECTION 2)
