50g of oxygen at NTP is compressed adiabatically to a pressure of 5 atmosphere. The work done on the gas, if gamma =1.4 and R = 8.31 J mol^(-1)K^(-1) is
Two litre of dry air at STP expands adiabatically to volume of 4 litres. If gamma 1.40 . The work done by air is (Take air to be an ideal gas ) (2^(1.4) =2.64) .
Two litre of dry air at STP expands adiabatically to volume of 4 litres. If gamma = 1.40 . The work done by air is (Take air to be an ideal gas ) (2^(1.4) =2.64) .
11.2 litre of a gas at STP weighs 14 g The gas could not be
1 gH_(2) gas STP is expanded so that the volume is doubled. Hence, work done is
A litre of dry air at STP expands isothermally to a volume of 3 litres. The work done by air is : (l n 3=1.1) [Take air to be an ideal gas]
One litre of a gas at STP weight 1.16 g it can possible be
1 moles of an ideal gas expanded spontaneously into vaccum. The work done will be
The volume of a certain mass of gas at a pressure of 5 xx 10 ^(4) Pa is doubled adiabatically. What is the final pressure of the gas ? [ gamma = 1.4]
The volume of a given mass of gas at NTP is compressed adiabatically to 1/5th of its original volume. What is the new pressure ? gamma =1.4.
VMC MODULES ENGLISH-JEE MAIN REVISON TEST-23-PHYSICS (SECTION 2)