A particle slides down a frictionless track AOC starting from rest at a point A (height 2m). After reaching on horizontal smooth track compresses a light spring of spring constant k=100n/m by distance 0.5 m before coming to rest. The height (in m) of horizontal track is ........... (Take `g = 10 m//s^(2))`

Answer

`0.75`

Explanation

`PE _(A)=PE _(C) + SPE _(C)implies mgh _(A) = mgh _(C)+ 1/2 kx ^(2)`
` implies h _(C)=h_(A) - (kx ^(2))/(2mg) =2m - (100xx1)/(2xx1xx10xx4) m`
`= (2-1.25)m" " =0.75m`