Home
Class 12
PHYSICS
The threshold frequency of a certain met...

The threshold frequency of a certain metal is `3.3xx10^(14)Hz`. If light of frequency `8.2xx10^(24)` Hz is incident on the metal, then the cut off voltage for photoelectric emission is `("Given h"=3.63xx10^(-34)Js)`

Text Solution

Verified by Experts

The correct Answer is:
2

`eV_(s)=h (v-v_(0)), " "V_(s)=(h (v-v_(0)))/(e) = (6.63xx10^(-34) (8.2-3.3)xx10^(14))/(1.6xx10^(-19)), V_(s) =2V`
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISON TEST-23

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|1 Videos
  • JEE Main Revision Test-9 | JEE-2020

    VMC MODULES ENGLISH|Exercise PHYSICS SECTION 2|5 Videos
  • KINEMATICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise JEE Advanced (archive)|14 Videos

Similar Questions

Explore conceptually related problems

The threshold frequency for a certain metal is 3.3xx10^(14) Hz. If light of frequency 8.2xx10^(14) Hz is incident on the metal, predict the cut-off voltage for the photoelectric emission.

The threshold frequency of a certain metal is 3.3xx10^(14)Hz . If light of frequency 8.2xx10^(14)Hz is incident on the metal, predict the cut off voltage for photoelectric emission. Given Planck's constant, h=6.62xx10^(-34)Js .

The threshold frequency of a certain metal is 3.3xx10^(14)Hz . If light of frequency 8.2xx10^(14)Hz is incident on the metal, predict the cut off voltage for photoelectric emission. Given Planck's constant, h=6.62xx10^(-34)Js .

The threshold frequency of a certain metal is 3.3xx10^(14)Hz . If light of frequency 8.2xx10^(14)Hz is incident on the metal, predict the cut off voltage for photoelectric emission. Given Planck's constant, h=6.62xx10^(-34)Js .

If light of frequency 8.2xx10^14 Hz is incident on the metal , cut-off voltage for photoelectric emission is 2.03 V.Find the threshold frequency . Given h= 6.63xx10^(-34) Js , e= 1.6xx10^(-19) C.

The threshold frequency of a material is 2xx10^14 Hz. What is its work function in eV ?

Frequency of a wave is 6 xx 10^(15) Hz. The wave is

Frequency of a wave is 6 xx 10^(15) Hz. The wave is

If the work function for a certain metal is 3.2 xx 10^(-19) joule and it is illuminated with light of frequency 8 xx 10^(14) Hz . The maximum kinetic energy of the photo-electrons would be (h = 6.63 xx 10^(-34) Js)

Threshold frequency of a certain metal for photoelectric emission is 5xx10^(14)Hz . Calculate its work function.