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The radius of gyration of a uniform disc...

The radius of gyration of a uniform disc of radius R, about an axis passing through a point `(R )/(2)` away from the centre of disc, and perpendicular to the plane of disc is:

A

`sqrt((1)/(2)) R`

B

`sqrt(2) R`

C

`(sqrt(3))/(2)R`

D

`(sqrt(3)/(4)) R`

Text Solution

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The correct Answer is:
To find the radius of gyration of a uniform disc of radius \( R \) about an axis passing through a point \( \frac{R}{2} \) away from the center of the disc and perpendicular to the plane of the disc, we can follow these steps: ### Step 1: Understand the Problem We need to calculate the radius of gyration \( k \) of a uniform disc about a specific axis (CD) that is located at a distance of \( \frac{R}{2} \) from the center of the disc. ### Step 2: Identify the Moment of Inertia The moment of inertia \( I \) of a uniform disc about its central axis (AB) is given by: \[ I_{AB} = \frac{1}{2} m R^2 \] where \( m \) is the mass of the disc and \( R \) is the radius of the disc. ### Step 3: Apply the Parallel Axis Theorem To find the moment of inertia about the axis CD, we use the parallel axis theorem, which states: \[ I_{CD} = I_{AB} + m d^2 \] where \( d \) is the distance between the two axes. Here, \( d = \frac{R}{2} \). ### Step 4: Calculate the Moment of Inertia about Axis CD Substituting the values into the equation: \[ I_{CD} = \frac{1}{2} m R^2 + m \left(\frac{R}{2}\right)^2 \] Calculating \( m \left(\frac{R}{2}\right)^2 \): \[ m \left(\frac{R}{2}\right)^2 = m \frac{R^2}{4} \] Now substituting this back into the equation for \( I_{CD} \): \[ I_{CD} = \frac{1}{2} m R^2 + m \frac{R^2}{4} = \frac{2}{4} m R^2 + \frac{1}{4} m R^2 = \frac{3}{4} m R^2 \] ### Step 5: Calculate the Radius of Gyration The radius of gyration \( k \) is defined as: \[ k = \sqrt{\frac{I_{CD}}{m}} \] Substituting \( I_{CD} \) into this formula: \[ k = \sqrt{\frac{\frac{3}{4} m R^2}{m}} = \sqrt{\frac{3}{4} R^2} = \sqrt{\frac{3}{4}} R = \frac{\sqrt{3}}{2} R \] ### Final Answer Thus, the radius of gyration of the uniform disc about the specified axis is: \[ k = \frac{\sqrt{3}}{2} R \]

To find the radius of gyration of a uniform disc of radius \( R \) about an axis passing through a point \( \frac{R}{2} \) away from the center of the disc and perpendicular to the plane of the disc, we can follow these steps: ### Step 1: Understand the Problem We need to calculate the radius of gyration \( k \) of a uniform disc about a specific axis (CD) that is located at a distance of \( \frac{R}{2} \) from the center of the disc. ### Step 2: Identify the Moment of Inertia The moment of inertia \( I \) of a uniform disc about its central axis (AB) is given by: \[ ...
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