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Three point particles of masses 1.0 k...

Three point particles of masses 1.0 kg, 1.5 kg and 2.5 kg are placed at three corners of a right angle triangle of sides 4.0 cm, 3.0 cm and 5.0 cm as shown in the figure. The center of mass of the system is at a point :

A

The centre of mass is 2.8 cm to the right and 1.7 cm above the 0.50 kg particle

B

The centre of mass is 2.2 cm to the right and 1.8 cm above the 0.50 kg particle

C

The centre of mass is 2.1 cm to the right and 1.7 cm above the 0.50 kg particle

D

The centre of mass is 1.3 cm to the right and 1.5 cm above the 0.50 kg particle

Text Solution

Verified by Experts

The correct Answer is:
D
Take origin at 0.50 kg mass
y = Vertical, x = horizontal
`X_(c.m) = (0.50 (0) + 1 xx 4 + 1.4 xx (0))/(0.50 + 1 + 1.5)`
`x_(c.m) = (4)/(3)`, `y_(c.m) = (0.50 (0) + 1 (0) + 1.53 (3))/(0.50 + 1 + 1.5)`
`y_(c.m) = (4.5)/(3)`, `y_(c.m) = 1.5 cm`
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