The real coefficient of volume expansion of glycerine is `0.000597per^(@)C` and linear coefficient of expansion of glass is `0.000009par^(@)C` . Then the apparent volume coefficient of glycerine is

Explanation

To find the apparent volume coefficient of glycerine, we can follow these steps:

### Step 1: Understand the formula for apparent volume coefficient
The apparent volume coefficient (\( \gamma_{\text{apparent}} \)) is given by the formula:
\[ \gamma_{\text{apparent}} = \gamma_{\text{glycerine}} - \gamma_{\text{glass}} \]
where \( \gamma_{\text{glycerine}} \) is the real coefficient of volume expansion of glycerine and \( \gamma_{\text{glass}} \) is the volume coefficient of glass.

### Step 2: Identify the given values
From the problem statement, we have:
- \( \gamma_{\text{glycerine}} = 0.000597 \, \text{per} \, ^\circ C \)
- The linear coefficient of expansion of glass (\( \alpha_{\text{glass}} \)) is given as \( 0.000009 \, \text{per} \, ^\circ C \).

### Step 3: Calculate the volume coefficient of glass
The volume coefficient of expansion for glass can be calculated from its linear coefficient using the relation:
\[ \gamma_{\text{glass}} = 3 \times \alpha_{\text{glass}} \]
Substituting the value of \( \alpha_{\text{glass}} \):
\[ \gamma_{\text{glass}} = 3 \times 0.000009 = 0.000027 \, \text{per} \, ^\circ C \]

### Step 4: Substitute values into the formula for apparent volume coefficient
Now we can substitute the values of \( \gamma_{\text{glycerine}} \) and \( \gamma_{\text{glass}} \) into the formula for \( \gamma_{\text{apparent}} \):
\[ \gamma_{\text{apparent}} = 0.000597 - 0.000027 \]

### Step 5: Perform the subtraction
Calculating the above expression gives:
\[ \gamma_{\text{apparent}} = 0.000570 \, \text{per} \, ^\circ C \]

### Final Answer
Thus, the apparent volume coefficient of glycerine is:
\[ \gamma_{\text{apparent}} = 0.000570 \, \text{per} \, ^\circ C \]

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