Pressure difference between two cross sections of a venturimeter, of area `40 cm^(2)` & `20 cm^(2)` is 480 Pascals.Find the rate of flow of water in the ventrurimeter. ( Density of water `= 1000 Kgm^(-3) ` )

Options

A. `1200 cm^(3) //s`
B. ` 1600 sqrt( 2) cm^(3) //s `
C. ` 1600cm^(3) //s`
D. ` 1200 sqrt( 2) cm^(3) //s`

Explanation

To solve the problem of finding the rate of flow of water in the venturimeter, we will follow these steps:

### Step 1: Identify Given Values
- Area of the wider section (A2) = 40 cm² = 40 × 10⁻⁴ m² = 0.004 m²
- Area of the narrower section (A1) = 20 cm² = 20 × 10⁻⁴ m² = 0.002 m²
- Pressure difference (ΔP) = 480 Pa
- Density of water (ρ) = 1000 kg/m³

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