If aperture diameter of telescope is 10m and distance Moon and Earth is `4 xx 10^(5) Km`. With wavelength of lightis `5500 Å`. The minimum separation between objects on surface of Moon, so that they are just resolved is close to `:`

Options

A. 60 m
B. 30 m
C. 600 m
D. 300 m

Explanation

To solve the problem, we need to determine the minimum separation between two objects on the surface of the Moon that can be resolved by the telescope. We will use the formula for the angular resolution of a telescope.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Aperture diameter of the telescope, \( D = 10 \, \text{m} \)
- Distance from Earth to Moon, \( d = 4 \times 10^5 \, \text{km} = 4 \times 10^8 \, \text{m} \) (conversion from km to m)
- Wavelength of light, \( \lambda = 5500 \, \text{Å} = 5500 \times 10^{-10} \, \text{m} \) (conversion from Ångströms to meters)
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