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A galvanometer of 50 ohm resistance has ...

A galvanometer of 50 ohm resistance has 25 divisions. A current of `4 xx 10^(–4)` ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of :-

A

`2500 Omega` as a shunt

B

`2450 Omega` as a shunt

C

`2550 Omega` in series

D

`2450 Omega` in series

Text Solution

Verified by Experts

The correct Answer is:
D
Full deflection current `i_(g) = 25 xx 4 xx 10^(-4) = 100 xx 10^(-4) A`
Using `R = (V)/(I_(g)) - G = (25)/(100 xx 10^(-4)) - 50 = 2450 omega` in series.
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