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The correct order of ionic size of N^(3-...

The correct order of ionic size of `N^(3-), Na^(+), F^(-), Mg^(2+) and O^(2-)` and is :

A

`Mg^(2+) gt NA^(+) gt F^(-) gt O^(2-) lt N^(3-)`

B

`N^(3-)gtF^(-)gt O^(2-) lt Na^(+) gt Mg^(2+)`

C

`Mg^(2+) lt Na^(+) lt F^(-) lt O^(2-) lt N^(3-)`

D

`N^(3-) gt O^(2-) gt F^(-) gt Na^(+) lt Mg^(2+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order of ionic sizes for the ions \(N^{3-}, Na^{+}, F^{-}, Mg^{2+},\) and \(O^{2-}\), we need to analyze the number of electrons and protons in each ion, as well as the concept of effective nuclear charge. ### Step-by-Step Solution: 1. **Identify the Ions and Their Electron Configurations:** - \(N^{3-}\): Nitrogen has 7 protons and gains 3 electrons, resulting in 10 electrons. - \(Na^{+}\): Sodium has 11 protons and loses 1 electron, resulting in 10 electrons. - \(F^{-}\): Fluorine has 9 protons and gains 1 electron, resulting in 10 electrons. - \(Mg^{2+}\): Magnesium has 12 protons and loses 2 electrons, resulting in 10 electrons. - \(O^{2-}\): Oxygen has 8 protons and gains 2 electrons, resulting in 10 electrons. 2. **Determine the Effective Nuclear Charge (Z_eff):** - The effective nuclear charge increases with the number of protons while the number of electrons remains constant. - \(N^{3-}\) has 7 protons, \(Na^{+}\) has 11 protons, \(F^{-}\) has 9 protons, \(Mg^{2+}\) has 12 protons, and \(O^{2-}\) has 8 protons. 3. **Analyze the Ionic Sizes:** - The ionic size increases with the addition of electrons (more electron-electron repulsion) and decreases with the loss of electrons (higher effective nuclear charge). - Thus, the order of ionic sizes will be inversely related to the number of protons (higher protons lead to smaller size). 4. **Order the Ions Based on Their Sizes:** - \(N^{3-}\) (7 protons, largest size due to high electron repulsion) - \(O^{2-}\) (8 protons) - \(F^{-}\) (9 protons) - \(Na^{+}\) (11 protons) - \(Mg^{2+}\) (12 protons, smallest size) 5. **Final Order of Ionic Sizes:** - The correct order of ionic sizes from largest to smallest is: \[ N^{3-} > O^{2-} > F^{-} > Na^{+} > Mg^{2+} \]

To determine the correct order of ionic sizes for the ions \(N^{3-}, Na^{+}, F^{-}, Mg^{2+},\) and \(O^{2-}\), we need to analyze the number of electrons and protons in each ion, as well as the concept of effective nuclear charge. ### Step-by-Step Solution: 1. **Identify the Ions and Their Electron Configurations:** - \(N^{3-}\): Nitrogen has 7 protons and gains 3 electrons, resulting in 10 electrons. - \(Na^{+}\): Sodium has 11 protons and loses 1 electron, resulting in 10 electrons. - \(F^{-}\): Fluorine has 9 protons and gains 1 electron, resulting in 10 electrons. ...
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