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The ratio of the radius difference betwe...

The ratio of the radius difference between `4^(th)` and `3^(rd)` orbit of H-atom and that of `Li^(2+)` ion is :

A

`1 : 1`

B

`3 : 1`

C

`3 : 4`

D

`9 : 1`

Text Solution

Verified by Experts

The correct Answer is:
B
`r_(4th) - r_(3rd) = (a_(0))/(z) [4^(2) - 3^(2)] therefore r_(H^(+))/(r_(Li^(2+))) = (3)/(1)`
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