The major product of the following equation is.
`C_(2)H_(5)-overset(CH_(3))overset("| ")underset(Ph)underset("| ")"C "-CH_(2)-underset(OH)underset("| ")"CH"-CH_(3)overset("conc. "H_(2)SO_(4))underset(Delta)rarr`

Options

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Explanation

To solve the problem, we need to determine the major product of the given reaction involving an alcohol and concentrated sulfuric acid. Here’s a step-by-step breakdown of the reaction:

### Step 1: Identify the Reactant
The reactant is an alcohol with the structure:
\[ C_2H_5 - C(CH_3) - C(Ph) - CH_2 - CH(OH) - CH(CH_3) \]

### Step 2: Protonation of the Alcohol
When concentrated sulfuric acid (H₂SO₄) is added, the hydroxyl group (OH) of the alcohol gets protonated to form a better leaving group (water). The reaction can be represented as:
\[ C_2H_5 - C(CH_3) - C(Ph) - CH_2 - CH(OH) \xrightarrow{H_2SO_4} C_2H_5 - C(CH_3) - C(Ph) - CH_2 - CH_2OH_2^+ \]

### Step 3: Formation of a Carbocation
The protonated alcohol (OH₂⁺) is a good leaving group and can leave, forming a carbocation. The reaction proceeds as follows:
\[ C_2H_5 - C(CH_3) - C(Ph) - CH_2^+ \]

### Step 4: Carbocation Rearrangement
The carbocation formed can rearrange to form a more stable carbocation. In this case, the positive charge can migrate to the adjacent carbon to form a more stable tertiary carbocation:
\[ C_2H_5 - C(CH_3) - C(Ph) - CH^+ - CH_3 \]

### Step 5: Elimination to Form the Alkene
In the presence of heat, the carbocation undergoes elimination (E1 mechanism) to form a double bond. The elimination can occur by removing a hydrogen atom from the adjacent carbon, leading to the formation of the alkene:
\[ C_2H_5 - C(CH_3) - C(Ph) = CH - CH_3 \]

### Step 6: Determine the Major Product
The stability of the alkene is determined by the number of substituents on the double bond. The more substituted the double bond, the more stable it is. Therefore, the major product will be the most stable alkene formed from the elimination step.

### Final Structure of the Major Product
The major product can be represented as:
\[ C_2H_5 - C(CH_3) - C(Ph) = CH - CH_3 \]

### Conclusion
The major product of the reaction is:
\[ C_2H_5 - C(CH_3) - C(Ph) = CH - CH_3 \]