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Consider the equation |x^2-2x- 3|=m .m b...

Consider the equation |x^2-2x- 3|=m .m belongs to R .If the given equation has four solutions, then `m in (0,oo)` b. `m in (-1,3)` c. `m in (0,4)` d. None of these

A

`m in (0,oo)`

B

`m in (-1,3)`

C

`m in (0,4)`

D

None of these

Text Solution

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The correct Answer is:
To solve the equation |x² - 2x - 3| = m, we need to analyze the quadratic function f(x) = x² - 2x - 3 and determine the conditions under which the absolute value equation has four solutions. ### Step 1: Find the roots of the quadratic equation First, we need to find the roots of the quadratic equation f(x) = x² - 2x - 3 = 0. Using the factorization method: - We can rewrite the equation as: \[ x² - 2x - 3 = (x - 3)(x + 1) = 0 \] - The roots are: \[ x = 3 \quad \text{and} \quad x = -1 \] ### Step 2: Analyze the graph of the quadratic function The graph of the quadratic function f(x) = x² - 2x - 3 is a parabola that opens upwards. The vertex of the parabola can be found using the vertex formula \( x = -\frac{b}{2a} \): - Here, \( a = 1 \) and \( b = -2 \): \[ x = -\frac{-2}{2 \cdot 1} = 1 \] - Now, substituting \( x = 1 \) back into f(x) to find the y-coordinate of the vertex: \[ f(1) = 1² - 2(1) - 3 = 1 - 2 - 3 = -4 \] - Thus, the vertex is at the point (1, -4). ### Step 3: Determine the behavior of the absolute value function Since we are considering the absolute value |f(x)|, the graph will reflect any negative portions of the parabola above the x-axis: - The points where f(x) = 0 are x = -1 and x = 3. - The vertex (1, -4) is below the x-axis, so the absolute value will create a "V" shape from this vertex. ### Step 4: Find the conditions for four intersections with the line y = m For the equation |f(x)| = m to have four solutions, the horizontal line y = m must intersect the graph of |f(x)| at four distinct points: - This occurs when the line y = m is above the vertex (1, -4) and below the maximum point of the absolute value function. - The maximum point occurs at the vertex of the original parabola, which is at y = -4. Therefore, for the line y = m to intersect the graph four times, m must be greater than 0 (to be above the x-axis) and less than 4 (to be below the maximum point of the absolute value function). ### Conclusion Thus, the condition for m is: \[ m \in (0, 4) \] From the given options, the correct answer is: **c. m in (0, 4)**
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