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If alpha and beta are the solution of ...

If `alpha and beta ` are the solution of ` a cos theta + b sin theta = c`, then

A

`sin alpha + sin beta =(2bc)/(a^2+b^2)`

B

`sin alpha sin beta =(c^2-a^2)/(a^2+b^2)`

C

`sin alpha + sin beta =(2ac)/(b^2-c^2)`

D

`sin alpha + sin beta =(c)/(a^2+b^2)`

Text Solution

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The correct Answer is:
A, B, C
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