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If cos alpha + cosbeta=a, sinalpha + sin...

If `cos alpha + cosbeta=a, sinalpha + sinbeta=b and theta ` is the arithmetic mean between `alpha` and `beta` , then `(sin2theta + cos 2theta)` is equal to :

A

`((a+b)^(2))/(a^2 + b^2)`

B

`((a-b)^(2))/(a^2 + b^2)`

C

`(a^(2)-b^(2))/(a^2 + b^2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
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