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"cos"(2001)pi+"cot"(2001) pi/2+sec(2001)...

`"cos"(2001)pi+"cot"(2001)` `pi/2+sec(2001)pi/3+tan(2001)pi/4+cos e c(2001)pi/6` equal to 0 (b) 1 (c) `-2` (d) not defined

A

0

B

1

C

-2

D

Not defined

Text Solution

Verified by Experts

The correct Answer is:
C
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