If `((1+i)/(1-i))^(2) - ((1-i)/(1+i))^(2) = x + iy` then find (x,y).

If ((1+i)/(1-i))^3-((1-i)/(1+i))^3=x+i y ,\ fin d\ (x , y)

If ((1+i)/(1-i))^3-((1-i)/(1+i))^3=x+i y ,\ fin d\ (x , y)

If ((1+i)/(1-i))^2=x+i y , find x+ydot

If (-2-(1)/(3)i)^(3)= (x+iy)/(27),xy, in R then y-x equals

" "(1+i)^(2)/(2-i)= x+ iy, "then find the value of x+y" .

" "(1+i)^(2)/(2-i)= x+ iy, "then find the value of x+y" .

If ( 1+i) (1+ 2i) (1+ 3i) …(1 +ni) = x+ iy, then 2,5,10 ….( 1+n^(2)) = x^(k) +y^(k) The value of k is :

If Sigma_( i = 1)^( 2n) sin^(-1) x_(i) = n pi , then find the value of Sigma_( i = 1)^( 2n) x_(i) .

If n= 10, sum_(i=1)^(10) x_(i) = 60 and sum_(i=1)^(10) x_(i)^(2) = 1000 then find s.d.

The number of real solution of the equation sin^(-1) (sum_(i=1)^(oo) x^(i +1) -x sum_(i=1)^(oo) ((x)/(2))^(i)) = (pi)/(2) - cos^(-1) (sum_(i=1)^(oo) (-(x)/(2))^(i) - sum_(i=1)^(oo) (-x)^(i)) lying in the interval (-(1)/(2), (1)/(2)) is ______. (Here, the inverse trigonometric function sin^(-1) x and cos^(-1) x assume values in [-(pi)/(2), (pi)/(2)] and [0, pi] respectively)