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If the cube roots of unity are 1,omega,o...

If the cube roots of unity are `1,omega,omega^2,` then the roots of the equation `(x-1)^3+8=0` are a. `-1,1+2omega,1+2omega^2` b. `-1,1-2omega,1-2omega^2` c. `-1,-1,-1` d. none of these

A

`-1,1 + 2 omega , 1+ 2 omega ^(2)`

B

`-3, -1- 2omega , -1-2omega ^(2)`

C

`-1, 1, -1`

D

None of these

Text Solution

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The correct Answer is:
B
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